Question

root of the equation x^2 +(2p-1)x +p=0 are real if​

Answer 1

Step-by-step explanation:

let the root of the equation be real then

b²-2ac=0

so we will apply this in the given equation.

(2p-1)²-2×1×p=0

4p²+1-4p-2p=0

4p²-6p+1=0

using the quadratic formula we can find the value of p.