Root over sec theta minus 1 by sec theta + 1 + root over sec theta + 1 by sec theta minus 1 equal to 2 cosec theta
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Step-by-step explanation:
on cross multipling the denominators from both sides we get
(sec∅ + 1 + sec∅ - 1) /√(sec²∅-)
this simplifies as 2sec∅/√tan²∅ (Since Sec²∅ - 1 = tan²∅)
=> 2sec∅/tan∅ (changing sec∅ to 1/cos∅ and tan∅ to sin∅/cos∅)
=>2/sin∅ = 2cosec∅
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