Question

Root over sec theta minus 1 by sec theta + 1 + root over sec theta + 1 by sec theta minus 1 equal to 2 cosec theta

Answer 1

Answer:

Step-by-step explanation:

on cross multipling the denominators from both sides we get

(sec∅ + 1 + sec∅ - 1) /√(sec²∅-)

this simplifies as 2sec∅/√tan²∅   (Since Sec²∅ - 1 = tan²∅)

=> 2sec∅/tan∅  (changing sec∅ to 1/cos∅ and tan∅ to sin∅/cos∅)

=>2/sin∅ = 2cosec∅