root over sec²theta +cosec ²theta = pls help any one..
ShreyaS05455:
secant is reciprocal of cos
y'a so.....
she said she will not give answers
??
will she explain or no
who ma'am.....
she gave homework who knows she will give or not
Shreyas I think u should thank him he saved us... ri8
is that answer correct
ya it's absolutely correct
Answers
Answered by
4
Answer:
tanθ + cotθ
Step-by-step explanation:
Given Equation is √sec²θ + cosec²θ
= √(1 + tan²θ) + (1 + cot²θ)
= √2 + tan²θ + cot²θ
= √tan²θ + cot²θ + 2 * 1
= √tan²θ + cot²θ + 2 * tanθ * (1/tanθ)
= √tan²θ + cot²θ + 2 tanθ cotθ
= √(tanθ + cotθ)²
= tanθ + cotθ
Hope it helps!
thank alot u saved me from punishment.....
:-)
Answered by
1
√sec²θ + cosec²θ
√(1 + tan²θ) + (1 + cot²θ)
√2 + tan²θ + cot²θ
√tan²θ + cot²θ + 2 * 1
√tan²θ + cot²θ + 2 * tanθ * (1/tanθ)
√tan²θ + cot²θ + 2 tanθ cotθ
√(tanθ + cotθ)²
tanθ + cotθ
thanks Siddhartha
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