Question

Root-root2/root3+root2=y and root3+root2/root3-root2=x,find x+y

Answer 1

Please see the attachment

Answer 2

Answer:

10

Step-by-step explanation:

x=$x=\frac{\sqrt{3} -\sqrt{2}}{\sqrt{3} +\sqrt{2}} \\=\frac{(\sqrt{3} -\sqrt{2})^{2}}{(\sqrt{3})^{2} -(\sqrt{2}) ^{2} }\\=5-2\sqrt{6}$

Similarly, by rationalising

$y=5+2\sqrt{6}$

∴

$x+y\\=5-2\sqrt{6} +5-2\sqrt{6} \\=10$