Question

root (sec^2theta+cosec ^2theta )=
plz answer this question ​

Answer 1

Question :

$\sqrt{ { \sec( \theta) }^{2} + { \csc( \theta) }^{2} }$

Answer :

$\: sec \theta \: cosec \theta$

Explanation :

$\sqrt{ { \sec( \theta) }^{2} + { \csc( \theta) }^{2} } = \sqrt{ \frac{1}{ { \cos( \theta) }^{2} } + \frac{1 }{ { \sin( \theta) }^{2} } }$

$\implies \: \sqrt{ \frac{ { \sin( \theta) }^{2} + { \cos( \theta) }^{2} }{ { \cos( \theta) }^{2} { \sin( \theta) }^{2} } }$

but we know that

${ \sin( \theta) }^{2} + { \cos( \theta) }^{2} = 1$

$\implies \sqrt{ \frac{1}{ { \cos( \theta) }^{2} { \sin( \theta) }^{2} } }$

$\implies \: \frac{1}{ \sqrt{ { \cos( \theta) { \sin( \theta) } }^{2} } }$

$\implies \: sec \theta \: cosec \theta$

Refer the above pic for another answer !.

Answer 2

Answer:

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