Math, asked by santhoshkrishna8, 11 months ago

root(sec square theta + cosec square theta) = tan theta +cot theta

Answers

Answered by sandy1816

4

Step-by-step explanation:

√sec²θ+cosec²θ

=√1+tan²θ+1+cot²θ

=√tan²θ+cot²θ+2

=√(tanθ+cotθ)²

=tanθ+cotθ

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