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![\sqrt[5]{5}x+2 = 2 \\ find \: the \: value \: of \: x](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B5%7Dx%2B2++%3D+2+%5C%5C+find+%5C%3A+the+%5C%3A+value+%5C%3A+of+%5C%3A+x "\sqrt[5]{5}x+2 = 2 \\ find \: the \: value \: of \: x")
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sqrt[5]{5}x + 2 = 2
sqrt[5]{5}x = 2-2
sqrt[5]{5}x = 0
so x = 0
is the answer.
sqrt[5]{5}x = 2-2
sqrt[5]{5}x = 0
so x = 0
is the answer.
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