Question

Root under 2sin square 38 degree plus 3 plus 2 sun square 52 degree by 3cosec square 17 degree minus 2 minus 3Tan square 73 degree

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

√5

Step-by-step explanation:

$\sqrt{ \frac{2 { \sin }^{2}(38) + 3 + 2 { \sin}^{2} (52) }{3 { \csc}^{2}(17) - 2 - 3 { \tan}^{2}(73) } }$

sinx =cos(90-x)

sin 52 = cos38

cosecx = sec( 90-x)

cosec 17 = sec73

$\sqrt{ \frac{2 { \sin }^{2}(38) + 3 + 2 { \cos}^{2} (38) }{3 { \sec}^{2}(73) - 2 - 3 { \tan}^{2}(73) } }$

${ \sin }^{2} (x) + { \cos }^{2} (x) \: = 1$

${ \sec }^{2} (x) - { \cos }^{2} (x) \: = 1$

$= \sqrt{ \frac{2 + 3}{3 - 2} } \\ = \sqrt{ \frac{5}{1} } \\ = \sqrt{5}$