root under 7 time 7
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Let x=√7√7√7√7....
=>x²=7√7√7√7
=>x²-7=x
=>x²-x-7=0
a=1 , b=-1 ,c=-7
x=-b±√b²-4ac/2a
x=1±√(-1)²-4(1)(-7)/2×1
=1±√1+28/2
=1±√29/2
=>x²=7√7√7√7
=>x²-7=x
=>x²-x-7=0
a=1 , b=-1 ,c=-7
x=-b±√b²-4ac/2a
x=1±√(-1)²-4(1)(-7)/2×1
=1±√1+28/2
=1±√29/2
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