root x + 1 - root x minus 1 equals to 1 then find the value of x
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Answer:
x=√17/4
Step-by-step explanation:
(√x+1)-(√x-1)=1
SQUARING BOTH SIDES
X+1-2(√X^2-1^1)-(X-1)=1. [(A+B)(A-B)=A^2-B^2]
-2√X^2-1=1/2
4(X^2-1)=1/4
X^2-1=1/16
X^2=1/16+1
X^2=17/16
TAKING SQ ROOT BOTH
X^2=√17/4
HOPE THIS HELPED YOU PLZZZ BRAINLIEST ME☺☺☺☺
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