root2+root2+root (2+cos8a)
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root12+cos8a
I hope that I am correct
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Answer:
√ (2 + √ (2 + √(2 + 2cos8)))
= √ (2 + √ (2 + √(2(1 + cos8)))
= √ (2 + √ (2 + √(4 cos24)))
= √ (2 + √ (2 + 2cos4))
= √ (2 + √ (2 (1+ cos4))
= √ (2 + √ (4 cos22))
= √ (2 + 2cos2)
= √ (2 (1+ cos2)
= √ 4 cos20
= 2cos0 PROVED
dikshu63:
thanks for helping me
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