Question

root2+root3 divided by root18-root12

Answer 1

Answer:

$\frac{12 + 5 \sqrt{5} }{6}$

Step-by-step explanation:

Given:-

$\frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{18} - \sqrt{12} }$

Solution:-

$\frac{ \sqrt{2} + \sqrt{3} }{{3 \sqrt{2} - 2 \sqrt{3 } } } \\ = \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ = \frac{6 + 2 \sqrt{5} + 3 \sqrt{5} + 6}{6} \\ = \frac{12 + 5 \sqrt{5} }{6}$