Root2 ( sinx+ cosx) =root 3
Anonymous:
what we have to find
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√2(sinx+cosx)=√3
sinx+cosx=√(3/2)
√2sin(x-π/4)=√(3/2)
sin(x-π/4)=sinπ/6
x-π/4=nπ+(-1)^nπ/6
sinx+cosx=√(3/2)
√2sin(x-π/4)=√(3/2)
sin(x-π/4)=sinπ/6
x-π/4=nπ+(-1)^nπ/6
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