Question

root2 x2 + 7x+5 root2 factorise it
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Answer 1

Answer:

$\sqrt{2} x {}^{2} \times 2 + 7x + 5 \sqrt{2} \\ 2 \sqrt{2 }x {}^{2} + 7x + 5 \sqrt{2} = 0$

then you solve it you get answer

I HOPE IT HELPS YOU

Answer 2

DEAR FRIEND HERE IS YOUR ANSWER:-

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ = > \sqrt{2} {x}^{2} + 5x + 2x + 5 \sqrt{2} = 0 \\ = > x( \sqrt{2} x + 5) + \sqrt{2} ( \sqrt{2} x + 5) = 0\\ = > (\sqrt{2} x + 5)(x + \sqrt{2} ) = 0 \\ \\ so \: \: x = \frac{ - 5}{ \sqrt{2} } \: \: or \: \: x = - \sqrt{2}$

THANKS ☺️☺️