root2 x²-root3x+root5=0 solve the equation
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Answer:
2√3x² - 5x + √3 = 0
2√3x²-3x - 2x + √3 = 0
√3x(2x - √3)-1(2x - √3)= 0
(2x - √3)(√3x - 1) = 0
x = √3/2, 1/√/3
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