Question

root2xsquare +7x+5root2 =0​

Answer 1

Step-by-step explanation:

√2x^2+7x+5√2=0

√2x^2+2x+5x+5√2=0

√2x(x+√2)+5(x+√2)=0

(x+√2)(√2x+5)=0

(x+√2)= 0 , (√2x+5)=0

x=-√2 , x=-5/√2

x=-1.414 , x= - 3.54

x= -1.414 or -3.54