Math, asked by smtpuspa45, 5 months ago

root3(1+tan15)=1-tan 15​

Answers

Answered by ashna145f
3

Answer:

(1+tan15)/(1-tan15)=(1+tan15)^2/(1-tan^2 15)=(1+2tan 15+tan^2 15)×cos^2 15/(cos^2 15-sin^2 15)=(cos^2 15+2sin 15×cos^2 15/cos 15+sin^2 15×cos^2 15/cos^2 15)/cos 30=(cos^2 15+sin^2 15+2sin 15.cos 15)×2/(3)^1/2=(1+sin30)2/(3)^1/2=(2+2.1/2)÷(3)^1/2=3÷(3)^1/2=(3)^1/2 ans.

Answered by jitukumar123456143
0

√3(+ tan 15°)=1 -tan 15°

Similar questions
Math, 2 months ago