Question

Root3 cot a=3 then sec a and sina + cosa

Answer 1

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Answer 2

Step-by-step explanation:

Given cube root of cota=3

Cota=3³

Cota=27

Cota=adj/opp=27/1

opp²+adj²=hyp²

1+27²=hyp²

hyp=Square root of 730

Seca=hyp/adj

Seca=

$\sqrt{730 } \div 27$

Sina+Cosa=

opp/hyp +adj/hyp

$1 \div \sqrt{730} + 27 \div \sqrt{730}$

$28 \div \sqrt{730}$