Math, asked by narenkarthik, 10 months ago

root3+root2by5+root2

Answers

Answered by vishakhakhanna2004

Step-by-step explanation:

$\sqrt{3} + \sqrt{2} \div 5 + \sqrt{2}$

$(5 \sqrt{3} + \sqrt{2} + 5 \sqrt{2} ) \div 5$

$(5 \sqrt{3} + 6 \sqrt{2} ) \div 5$

further steps are in the attachment

Attachments:

akshay4120: i think there is mistake

narenkarthik: ok it's you have helped me and thanks

vishakhakhanna2004: ur wlkm

vishakhakhanna2004: akshay plz tell me my mistake so that i can edit.

akshay4120: 6 ko aapne√2and √3 liya h .how?

akshay4120: i think jb same number hote h tb hm ye formula use krte h jo aapne kiya h

akshay4120: m glt bhe ho skta hu so please correct

vishakhakhanna2004: yes u r right. actually mujhe lga ki vo root 6 h....thank

akshay4120: anytime bro

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