Math, asked by 205, 1 year ago

Root3x^2 - 2root2+ 2root3 = 0

Answers

Answered by Anonymous
3

Answer:

Hey Mate...

Step-by-step explanation:

√3 x^2 - 2√2 x - 2√3=0

√3 x^2 - 3√2 x + √2x -2√3 =0

 

√3 x(x- √6) + √2(x- √6)=0

 

(√3 x + √2)(x - √6)=0

x = -√2/√3 or √6

Thank you...

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