Math, asked by anushajain8741, 1 year ago

Root3x^2 - 2root2xÃ-2root3=0

Answers

Answered by mysticd
0

Required roots

x = -√2/√3 or x = √6

Explanation:

√3x²-2√2x-2√3 = 0

Splitting the middle term, we get

=> √3x²+√2x-3√2x-2√3=0

=> x(√3x+√2)-√6(√3x+√2)=0

=> (√3x+√2)(x-√6)=0

=> √3x+√2=0 or x-√6 = 0

=> x = -√2/√3 or x = √6

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