Root3x^2 - 2root2xÃ-2root3=0
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Required roots
x = -√2/√3 or x = √6
Explanation:
√3x²-2√2x-2√3 = 0
Splitting the middle term, we get
=> √3x²+√2x-3√2x-2√3=0
=> x(√3x+√2)-√6(√3x+√2)=0
=> (√3x+√2)(x-√6)=0
=> √3x+√2=0 or x-√6 = 0
=> x = -√2/√3 or x = √6
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