Question

root3x2-2x+root3=0 find two zero of this equation. ​

Answer 1

Answer:

Brackets I used is not mandatory so use them as per u r wish.

Step-by-step explanation:

^3×2-2x+^3 = 0

^3×2-2x+^3 = 0 0=-3^2x

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷2

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0 0=-3^2x

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷2

^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1^3×2-2x+^3 = 0 0=-3^2x0=(-3×4x)0=x²0=4÷20=1