CBSE BOARD X, asked by pawni65, 1 month ago

(root5+2root2)square(root5-root8)square
Please answer my question
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Answers

Answered by jayeshpatil0903
0

(\sqrt{5}+2\sqrt{2})^{2} * (\sqrt{5} -\sqrt{8} )^{2} = (\sqrt{5}+2\sqrt{2})^{2} * (\sqrt{5} -\sqrt{4*2} )^{2}

                                         = (\sqrt{5}+2\sqrt{2})^{2} * (\sqrt{5} -2\sqrt{2} )^{2}

                                         = ((\sqrt{5}+2\sqrt{2}) * (\sqrt{5} -\sqrt{8} ))^{2}    

                                         = ((\sqrt{5})^{2} - (2\sqrt{2})^{2})^{2}

                                         = (5-4*2)^{2}

                                         = (5-8)^{2}

                                         =\\(-3)^{2}\\

                                         = 9

Answered by haha1277
0

Answer:

abe suar ki aulad bhul gayi kya mujhe khabeez

(

5

+2

2

)

2

∗(

5

8

)

2

= (\sqrt{5}+2\sqrt{2})^{2} * (\sqrt{5} -\sqrt{4*2} )^{2}(

5

+2

2

)

2

∗(

5

4∗2

)

2

= (\sqrt{5}+2\sqrt{2})^{2} * (\sqrt{5} -2\sqrt{2} )^{2}(

5

+2

2

)

2

∗(

5

−2

2

)

2

= ((\sqrt{5}+2\sqrt{2}) * (\sqrt{5} -\sqrt{8} ))^{2}((

5

+2

2

)∗(

5

8

))

2

= ((\sqrt{5})^{2} - (2\sqrt{2})^{2})^{2}((

5

)

2

−(2

2

)

2

)

2

= (5-4*2)^{2}(5−4∗2)

2

= (5-8)^{2}(5−8)

2

=\begin{gathered}\\(-3)^{2}\\\end{gathered}

(−3)

2

= 9

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