Question

(root5+root2/root5-root2)+(root5-root2/root5+root2)=a+b root10, find a and b.​

Answer 1

Answer:

a = 14/3 ; b = 0

Step-by-step explanation:

Given:

The given equation is $\frac{\sqrt{5}+\sqrt{2} }{\sqrt{5}-\sqrt{2} } + \frac{\sqrt{5}-\sqrt{2} }{\sqrt{5}+\sqrt{2} }$

⇒ $\frac{(\sqrt{5}+\sqrt{2} )^{2} + (\sqrt{5}-\sqrt{2})^{2} }{(\sqrt{5}-\sqrt{2})( \sqrt{5}+\sqrt{2} )}$

=> 2(5+2)/5-2

=> 2 × 7/ 3

⇒14/3

Hope it helps

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