Question

(Root5 +root7)(root5+root7)=?

Answer 1

Answer:

12 + 2√35

Step-by-step explanation:

Question:

$( \sqrt{5} + \sqrt{7} )( \sqrt{5} + \sqrt{7} )$

Identity Used:

(a+b)(a+b) = (a+b)²

(a+b)² = a² + b² + 2ab

Solution:

$( \sqrt{5} + \sqrt{7} )( \sqrt{5} + \sqrt{7} ) \\ = {( \sqrt{5} + \sqrt{7}) }^{2} \\ = {( \sqrt{5}) }^{2} + {( \sqrt{7}) }^{2} + 2 \times \sqrt{5} \times \sqrt{7} \\ = 5 + 7 + 2 \sqrt{35} \\ = 12 + 2 \sqrt{35}$

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Answer 2

Answer:

12+2√35

Step-by-step explanation:

(√5+√7) (√5+√7)

(√5+√7)^2

we know that,

(A+B)^2=A^2+B^2+2AB

Now,

(√5+√7)^2

(√5)^2+(√7)^2+ 2×√5×√7

5+7+2√35

12+2√35

If we take 2 common then,

2(6+√35)

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