root6/root3-root2 rationalise the denominator
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Answer:
answer is 3√2 + 2√3
Step-by-step explanation:
√6/(√3 - √2)
√6/(√3 - √2) × (√3 + √2)/(√3 + √2)
[√6(√3+√2]/[(√3)² - (√2)²
[√18 + √12]/[3 - 2]
[√(2×3×3) + √(2×2×3)]/1
3√2 + 2√3
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