Math, asked by adi278, 1 year ago

root7-1/root7+1-roor7+1/root7-1=a+broot7

Answers

Answered by MANKOTIA
0
√7-1/√7+1-√7+1/√7-1 tell me this question is correct..or not. I wrote correct question or not.
Answered by krrishkhedia
0

Answer:

(√7-1/√7+1)-(√7+1/√7-1)=a+b√7

or, {(√7-1)(√7-1)-(√7+1)(√7+1)}/{(√7+1)(√7-1)}=a+b√7

or, {(√7-1)²-(√7+1)²}/{(√7)²-(1)²}=a+b√7

or, (7-2√7+1-7-2√7-1)/(7-1)=a+b√7

or, (-4√7)/6=a+b√7

or, -2√7/3=a+b√7

or, 0+(-2/3)√7=a+b√7

Equating both sides,

a=0, b=-2/3

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