Question

roots for 3x^2–21x+18=0​

Answer 1

Answer:

Here is your answer...................

Answer 2

Answer:

therefore, roots r real and equal

Step-by-step explanation:

3x^2 - 21x + 18 = 0

=> 3 (x^2 - 7x + 6) = 0

=> x^2 - 7x + 6 = 0

a = 1 , b = -7 , c = 6

therefore,

b^2 - 4ac

= (-7)^2 - 4 * 1 * 6

= 49 - 24

= 25

hope it helps n u understand mate...