Question

roots of 4u square+8u​

Answer 1

Step-by-step explanation:

Let f(u)=4u

2

+8u

To calculate the zeros of the given equation, put f(u)=0.

4u

2

+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

a

−b

=

4

−(8)

=−2

The product of the zeros is,

a

c

=

4

0

=0

Hence, it is verified that,

sumofzeros=

coefficientofx

2

−coefficientofx

And,

productofzeros=

coefficientofx

2

constantterm