Question

roots of 4x square +2kx+1=0​

Answer 1

Answer:

4x2 + kx + 3 = 0 It’s of the form of ax2 + bx + c = 0 Where, a = 4, b = k, c = 3 For the given quadratic equation to have real roots D = b2 – 4ac ≥ 0 D = (k)2 – 4(4)(3) ≥ 0 ⇒ k2 – 48 ≥ 0 ⇒ k2 ≥ 48 ⇒ k ≥ 4√3 and k ≤ -4√3 [After taking square root on both sides] The value of k can be represented as (∞, 4√3] U [-4√3, -∞)Read more on Sarthaks.com - https://www.sarthaks.com/647612/find-the-values-of-k-for-equation-have-real-roots-4x-2-kx-3-0