Question

roots of equation x^2_7x+12=10​

Answer 1

Answer:

$\huge{\boxed{\rm{\red{Roots=3 and4}}}}$

Step-by-step explanation:

Given equation is x²-7x+12=0

=>x²-7x+12=0

=>x²-3x-4x+12=0

=>x(x-3)-4(x-3)=0

=>(x-3)(x-4)=0

=>x-3=0 (or) x-4=0

=>x=3 and 4

Roots are 3 and 4

Answer 2

Step-by-step explanation:

${x}^{2} - 7x + 12 = 0 \\ \\ = > {x}^{2} - 4x - 3x + 12 = 0 \\ \\ = > x(x - 4) - 3(x - 4) = (x - 3)(x - 4) = 0$

☆Hence roots of the equation are :

x-3=0=> x=3.

x-4=0 => x=4.