Question

roots of quadratic equation for y²-5y -24=0
plz help me guys .​

Answer 1

Answer:

-3, 8

Step-by-step explanation:

Answer 2

❤️❤️ꫝꫀꪶꪶꪮ❤️❤️

${y}^{2} + 5y - 24 = 0$

$for \: this \: equation = a = 1 | b = 5 | \\ c = - 24$

$1 {y}^{2} + 5y + - 24 = 0$

$use \: quadratic \: formula \: with$

$a = 1 | b = 5 | c = - 24$

$y = \frac{ - b( + - ) \sqrt{ {b}^{2} - 4ac} }{2a}$

$y = \frac{ - (5)( + - ) \sqrt{ {(5)}^{2} - 4(1)( - 24) } }{2(1)}$

$y = \frac{ - 5( + - ) \sqrt{121} }{2} \\ y = 3 \: or \: y = - 8$