Question

*Roots of quadratic equation x²– 3x = 0 , will be ………………..*

1️⃣ 3
2️⃣ 0,-3
3️⃣ 0,3
4️⃣ none of these​

Answer 1

Answer:

0, 3

Explanation:

x²– 3x = 0

Here,

a = 1

b = - 3

c = 0

D = b^2 - 4ac

   = ( - 3 )^2 - 4 ( 1 ) ( 0 )

   = 9 - 0

D = 9

x = ( - b ± √D ) / 2a

  = ( - ( - 3 ) ± √9 ) / 2 ( 1 )

  = ( 3 ± 3 ) / 2

  = ( 3 + 3 ) / 2, ( 3 - 3 ) / 2

  = 6 / 2, 0 / 2

x = 3, 0

The roots of quadratic equation x²– 3x = 0, will be 0, 3.

Answer 2

The given equation is $x^{2}-3x=0$.

We have to find its solution.

Step-by-step explanation:

Now, $x^{2}-3x=0$

Take $x$ common from the l.h.s. term:

$\Rightarrow x(x-3)=0$

It gives the consent to take either $x=0$ or $x-3=0$

$\Rightarrow x=0$ or $x=3$

Therefore the required solution is

$\quad\quad x=0,\:3$

Hence, Option 3️⃣ is correct.

Verification:

When $x=0\Rightarrow 0^{2}-3(0)=0$

When $x=3\Rightarrow 3^{2}-3(3)=0$

Thus verified.