roots of the equation x^2- 11 x + 28 is equals to zero are
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Heya ,
Your Answer. is here....
__________________________
Given :- x^2-11x+28
Sol.
Let the given polynomial be denoted by f(x).
Than,
f(x) = x^2- 11x + 28
=>x^2 - 7x - 4x +28
=> x( x - 7 ) - 4 ( x - 7 )
=> (x - 7) (x - 4)
• f(x )=0
=> (x - 7)(x - 4)=0
=>x -7 =0 or x - 4 =0
=> x = 0 + 7 or x =0 + 4
=> x = 7 or x = 4
so , the zeros of f (x ) are 7 and 4
☺☺
Your Answer. is here....
__________________________
Given :- x^2-11x+28
Sol.
Let the given polynomial be denoted by f(x).
Than,
f(x) = x^2- 11x + 28
=>x^2 - 7x - 4x +28
=> x( x - 7 ) - 4 ( x - 7 )
=> (x - 7) (x - 4)
• f(x )=0
=> (x - 7)(x - 4)=0
=>x -7 =0 or x - 4 =0
=> x = 0 + 7 or x =0 + 4
=> x = 7 or x = 4
so , the zeros of f (x ) are 7 and 4
☺☺
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