Math, asked by hare10, 1 year ago

roots of the equation x^2- 11 x + 28 is equals to zero are

Answers

Answered by Anonymous
5
Heya ,
Your Answer. is here....
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Given :- x^2-11x+28

Sol.
Let the given polynomial be denoted by f(x).
Than,

f(x) = x^2- 11x + 28

=>x^2 - 7x - 4x +28

=> x( x - 7 ) - 4 ( x - 7 )

=> (x - 7) (x - 4)

• f(x )=0

=> (x - 7)(x - 4)=0

=>x -7 =0 or x - 4 =0

=> x = 0 + 7 or x =0 + 4

=> x = 7 or x = 4

so , the zeros of f (x ) are 7 and 4


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