Question

roots of the equation X2 + 6 X + k A is equal to 0 are equal then the value of k is?​

Answer 1

Answer:

Given equation :  $x^2+6x+k=0$

=> Roots of the equation are equal

=> Discriminant (D) =  $b^2-4ac=0$

where a = 1 ; b = 6 ; c = k

=>  $6^2-4(1)(k)=0$

=> 36 - 4k = 0

=> 4k = 36

Therefore, k = 9