Roots of the equation x² + ax + b = 0 are in the ratio 1:2 then
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Let α,β be the roots of equation x2+px+q=0 and let γ,δ be the roots of equation x2+bx+c=0
Then, α+β=−p,αβ=q
and γ+δ=−b,γδ=c
Given, βα=δγ
Applying componendo-dividendo
α−βα+β=γ−δγ+δ
⇒(α−β)2(α+β)2=(γ−δ)2(γ+δ)2
⇒α2+β2−2αβp2=γ2+δ2−2γδb2
⇒(α+β)2−4αβp2=
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