Question

-
Roots of the quadratic equation
16x² - Kx + 1 = 0 are equal and real.
find the value of K.​

Answer 1

Answer:

Given x2+kx+k

Step-by-step explanation:

roots are real & equal

∴b2−4ac=0

=(k)2−4(1)(k)=0

=k2−4k=0

=k(k−4)=0

∴  k = 0 or k = 4

mark me as  brainliest

Answer 2

$\huge\underline{\sf GivEn:-}$

⭐ We have given a quadratic equation 16x² - Kx + 1 = 0

⭐ The roots of quadratic equation are real & equal.

$\huge\underline{\sf To\: Find:-}$

↪ Find the value of 'k'

$\huge\underline{\sf SoLutioN:-}$

The given equation is 16x² - Kx + 1 = 0

Here,

$\longrightarrow$ a = 16

$\longrightarrow$ b = -k

$\longrightarrow$ c = 1

↪ D = b² - 4ac

$\implies$ (-k)² - 4(16)(1)

$\implies$ k² - 64

The given equation will have real and equal roots, if

↪ D = 0

$\implies$ k² - 64 = 0

$\implies$ k² = 64

$\huge{\boxed{\bf{k = 8}}}$

$\huge\underline{\sf ThAnKs...}$