Math, asked by at0003342, 10 months ago

Roots of the Quadratic equation 2x^2-x-2=0are_____and____

Answers

Answered by waqarsd
5

Answer:

x =  \frac{1 +  \sqrt{17} }{4}  \\  \\ x =  \frac{1 -  \sqrt{17} }{4}  \\

Step-by-step explanation:

2 {x}^{2}  - x - 2 = 0 \\  \\ for \:  \: a {x}^{2}  + bx + c = 0 \\  \\ x =  \frac{ - b +  | \sqrt{ {b}^{2}  - 4ac} | }{2a}  \\  \\ here \\  \\ a = 2 \\ b =  - 1 \\ c =  - 2 \\  \\ x =  \frac{ - ( - 1) +  | \sqrt{ {( - 1)}^{2} - 4(2)( - 2) } |  }{2(2)}  \\  \\ x =  \frac{ 1 +  | \sqrt{17} | }{4}  \\  \\ x =  \frac{1 +  \sqrt{17} }{4}  \\  \\ x =  \frac{1 -  \sqrt{17} }{4}  \\  \\

HOPE IT HELPS

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