Roots of the quadratic equation (3x+1)(2x-2) = 0 are
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Answer:
(3x+1)(2x-2) = 0
6x² - 4x - 2 = 0
3x² - 2x - 1 = 0
Sum of roots = -b/a = 2/3
Product of roots = c/a = -1/3
From these two relations:
α = 1
β = -1/3
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