Roots of the quadratic equation 3x² + 2√6x + 2 = 0
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Step-by-step explanation:
3x² + 2√6x + 2 = 0
=> (√3x)² + 2 × √3x × √2 + (√2)² = 0
=> (√3x + √2)² = 0
=> √3x + √2 = 0
=> √3x = - √2
=> x = -√2/√3
Hence both roots are -√2/√3 , -√2/√3
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