Question

roots of the quadratic equation 6x^2-x-2=0 are​

Answer 1

Answer:

Step-by-step explanation:Hey !!!

By using spliting method you can find out roots of this quadratic equation .

6x² - x - 2 = 0

6x² - 4x+3x - 2 = 0

2x ( 3x - 2) -1 (3x - 2) = 0

(2x - 1)(3x - 2 ) = 0

2x - 1 = 0

x = 1/2

and 3x - 2 = 0

x = 2/3 here two roots = 1/2 and 3/2

These roots are greater than 0 so real and unequal roots we get

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Hope it helps you !!!  pls mark me as brainliest

Answer 2

Answer:

$6 {x}^{2} - x - 2 = 0$

$= > 6 {x}^{2} - 4x + 3x - 2 = 0$

$= > 2x(3x - 2) + 1(3x - 2) = 0$

$= > (2x + 1)(3x - 2) = 0$

$= > 2x + 1 = 0 \: or \: 3x - 2 = 0$

$= > x = \frac{ - 1}{2} \: or \: x = \frac{2}{3}$

Hope it helps you.