Math, asked by chchillar49, 10 months ago

Roots of the quadratic equation 9x2 - 3x -2 = 0 by factorisation are

Answers

Answered by shardasahil9525
5

Answer:

9x2-3x-2=0

9x2+3x-6x-2=0

3x(3x+1)-2(3x+1)=0

(3x+1) (3x-2)=0

3x+1=0

3x=0-1

3x=-1

x=-1/3.

3x-2=0

3x=0+2

3x=2

x=2/3

x=-1/3. ,x=2/3

Answered by vishal01316
1

Answer:

9x^2-3x-2=0

9x^2-3x-2=09x^2-6x+3x-2=0

9x^2-3x-2=09x^2-6x+3x-2=03x(3x-2)1(3x-2)=0

9x^2-3x-2=09x^2-6x+3x-2=03x(3x-2)1(3x-2)=0Either 3x+1=0 OR 3x-2=0

9x^2-3x-2=09x^2-6x+3x-2=03x(3x-2)1(3x-2)=0Either 3x+1=0 OR 3x-2=03x=-1 or 3x=2

9x^2-3x-2=09x^2-6x+3x-2=03x(3x-2)1(3x-2)=0Either 3x+1=0 OR 3x-2=03x=-1 or 3x=2x=-1/2or x=2/3

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