Question

Roots of the quadratic Equation x²-6ax+9a²-36b²=0 are
(1 Point)​

Answer 1

X^2-2(3a)(x)+(3b)^2- (6b)^2 =0
(X-3b)^2- (6b)^2 = 0
(X-3b+6b)(x-3b-6b)=0
(X+3b)(x-9b)=0
X=-3b , x=9b