Question

Roots of the quadratic equation x²
– 6x + 9 = 0 are​

Answer 1

Answer:

3,3

Step-by-step explanation:

x^2-6x+9=0

(x-3)^2=0

(x-3) (x-3)=0

x-3=0. or. x-3=0

x=3,3

Answer 2

Solution :-

We need to find the roots of quadratic equation x² - 6x + 9 = 0

Finding its roots by factorisation

Firstly by splitting the middle term

→ x² - x(3 + 3) + 9 = 0

→ x² - 3x - 3x + 9 = 0

Taking common

→ x(x - 3) - 3(x - 3) = 0

→ (x - 3)(x - 3) = 0

→ (x - 3)² = 0

→ x - 3 = 0

→ x = 3

Hence , x = 3 .

More information :-

More formulas

x = - b±√∆/2a

∆ or D , this is also known as determinant = b² - 4ac

Where

• b → coefficient of x
• a → coefficient of x²
• c → constant term