Question

Roots of x^2+x-2 by splitting method

Answer 1

Correct Question :-

Find the roots of the equation $\sf \ x^2 + x - 2$ by splitting method.

AnswEr :-

x = 2 and x = - 1

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Step by Step Explanation:-

$\longrightarrow\sf\; x^2 + x - 2$

$\longrightarrow\sf\; x^2 - 2x + 1 x - 2$

$\longrightarrow\sf\; x (x - 2) + 1 (x - 2)$

$\longrightarrow\sf\; (x + 1) (x - 2)$

$\longrightarrow\sf\; x + 1 = 0$

$\longrightarrow\large\boxed{\sf{\red{ x = - 1}}}$

$\longrightarrow\sf\; x - 2 = 0$

$\longrightarrow\large\boxed{\sf{\red{ x = 2}}}$

So, the roots of the Given equation are - 1 & 2.

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Answer 2

$\sf \huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

The polynomial is (x)² + x - 2

By middle term splitting method ,

$\sf \hookrightarrow {(x)}^{2} + x - 2 = 0 \\ \\\sf \hookrightarrow {(x)}^{2} - x + 2x - 2 = 0 \\ \\ \sf \hookrightarrow x(x - 1) + 2(x - 1) = 0 \\ \\ \sf \hookrightarrow (x + 2)(x - 1) = 0 \\ \\ \sf \hookrightarrow x = - 2 \: \: and \: \: x = 1$

Hence , the required values of x are - 2 and 1

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