Question

roots of xpower2+6x+5=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

${x}^{2} + 6x + 5 = 0 \\ \\ d = {b}^{2} - 4ac \\ \\ \\ \\ ( {6}^{2} - 4 \times 1 \times 5) \\ \\ = 36 - 20 \\ \\ = 16 \\ \\ \\ x = \frac{ - b \binom{ + }{ - } \sqrt{d} }{2a} \\ \\ = \frac{ - 6 \binom{ + }{ - } \sqrt{16} }{2 \times 1} \\ \\ \\ = \frac{ - 6 + 4}{2} = \frac{ - 2}{2} = - 1 \\ \\ \\ \\ = \frac{ - 6 - 4}{2} = \frac{ - 10}{2} = - 5$

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shortcut..

x^2+6x+5=

x^2+5x+x+5=

x(x+5)+1(x+5)

x=-5,-1