Question

Rootx+8 + rootx+5 =root 9x+40

Answer 1

Answer:

x=i3×root3

Step-by-step explanation:

$\sqrt{x} + 8 + \sqrt{x} + 5 = \sqrt{9x} + 40$

$2 \sqrt{x} + 13 = 3 \sqrt{x} + 40$

$- \sqrt{x} = 27$

$x = \sqrt{ - 27}$

$x = 3 \sqrt{ - 1 \times 3}$

$x = i3 \sqrt{3}$