Math, asked by amit6367, 1 year ago

Roshan loss 20% of his money after spending 25% of the remainder he has 4800 with him how much did he original have​

Answers

Answered by devaranjini1977
5

Answer:

Step-by-step explanation:

Let the total money Roshan has = Rs. x

Money lost = Rs. 20% of x

= Rs.(20/100)x

Remainder = Rs. x - (20/100)x

= Rs.(80/100)x

Money Spent = Rs. 25% of (80/100)x

= Rs. (20/100)x

Total money left =Rs. (80/100)x - (20/100)x

= Rs. (60/100)x

According to question,

(60/100)x = 4800

x = 4800(100/60)

x = 8000

Therefore, Roshan originally had Rs. 8000

Answered by brain111111
0

Answer:

let the original money roshan had is x

given that 1st he spends 25% of the original money

⇒ he spends 25x/100 money = x/4

the remaining money he had after spending is x - x/4 = 3x/4

now he loses 20% of his remaining money

⇒ he loses 3x/4 × 20/100 money = 3x/20

⇒ the remaining money of roshan after losing money is

⇒ (3x/4 - 3x/20) = 12x/20

given that remaining money after losing = 4800

⇒ 12x/20 = 4800

⇒ x = 8000

so the original money roshan had is 8000 Rs/-


brain111111: i need 3 more brainliest to become virtuoso so please mark brainliest
devaranjini1977: U just copied my answer and asking for brainliest!!!
brain111111: hey my method is totally different and the answers are supposed to be same idiot thats how u know its correct
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