Question

Rosie, Matilda and Ibrahim collect stickers.

number of stickers Rosie has : : number of stickers Matilda has : number of stickers Ibrahim has = 4 : 7 : 15


Ibrahim has 24 more stickers than Matilda.

Ibrahim has more stickers than Rosie.
How many more?

Answer 1

Step-by-step explanation:

Let the common ratio be = x

Rosie:Matilda:Ibrahim=4x:7x:15x

ATP

15x-7x=24

8x=24

x=3

let rosie take y less sticker than Ibrahim

15x-4x=y

8(3)=y

y=24

Rosie take 24 less sticker with respect of Ibrahim (ANSWER)

Answer 2

Answer:

Ibrahim has 33 stickers more than Roise    

Step-by-step explanation:

Given data

⇒ Number of stickers of Rosie : : number of stickers of Matilda : number of stickers of Ibrahim  = 4 : 7 : 15  

⇒ Ibrahim has 24 stickers than Matilda  

⇒ here we need to find How many stickers Ibrahim has more than Rosie

⇒ let 4x, 7x and 15x are be the number of stickers that are collected by Rosie, Matilda and Ibrahim respectively  

⇒ from given data Ibrahim has 24 stickers more than Matilda

⇒ number stickers ibrahim has - number of stickers Matilda = 24

⇒ 15x - 7x = 24 ⇒  8x =24 ⇒ x = 3

⇒ the number stickers collected by each    

            ⇒ Rosie = 4x = 4(3) =12

            ⇒ Matilda = 7x = 7(3) = 21

            ⇒ Ibrahim = 15x = 15(3) = 45  

⇒number of stickers Ibrahim has - number of stickers Rosie has

                                            =  45  -  12  =  33  

⇒ Ibrahim has 33 stickers more than Roise