Question

rot 5 is an irrational number provwe that 7+rooot 3 is an irrational no

Answer 1

Here is your answer.

Answer 2

Answer:

proved

Step-by-step explanation:

given $\sqrt{5}$ is an irrational number

let 7+$\sqrt{3}$ is a rational number and = x

so, 7+root 3 =x

root3=x-7

x is a rational number

x-7 is a rational number

therefore root3 will be a rational number

but root 3 is an irrational number

therefore our assumption is wrong

hence it is a contradiction and 7+root3 is an irrational number